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NTSE Sample Paper NTSE SAT Practice Test-12

  • question_answer
    A cube of side y is converted to a cuboid in such a way that three concurrent edges are in the ratio 1:2:4 and the shorter edge is x. What is the ratio of the surface area of the cuboid to that of the cube?

    A) 7 : 6      

    B) 7 : 12

    C) 11 : 10             

    D) 10: 11

    Correct Answer: A

    Solution :

    [a] \[{{y}^{3}}=4x\times 2x\times x=8{{x}^{3}}\] or \[y=2x\] \[\frac{Surface\text{ }area\text{ }of\text{ }cuboid}{Surface\text{ }area\text{ }of\text{ }cube}\]\[=\frac{2(2{{x}^{2}}+4{{x}^{2}}+8{{x}^{2}})}{6{{y}^{2}}}\] \[=\frac{28{{x}^{2}}}{24{{x}^{2}}}\] \[=\frac{7}{6}\]                        


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