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NTSE Sample Paper NTSE SAT Practice Test-11

  • question_answer
    In the figure ABCD is a parallelogram. P is a point on BC such that PB : PC = 1 : 2. DP produced meets AB produced at Q. If the area of the triangle BPQ is 20 square units, what is the area of the triangle DCP?

    A) 20 sq.units        

    B) 30 sq.units

    C) 40 sq.units        

    D) None of these

    Correct Answer: D

    Solution :

    [d] BP : PC = 1 : 2, so the triangles BPQ and DPC are similar whose sides are in the ratio 1 :2 \[\Rightarrow \]Areas, are in the ratio 1 : 4. \[~\therefore \,\,\Delta \,DCP\]is of the area \[4\text{ }\times 20\]i.e. 80 sq. units.


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