A) \[600\text{ }g\]
B) \[1000\text{ }g\]
C) \[1250\text{ }g\]
D) \[2000g\]
Correct Answer: D
Solution :
\[{{t}_{{\scriptstyle{}^{1}/{}_{2}}}}=10\] days \[T=40\] days \[n=\frac{T}{{{t}_{{\scriptstyle{}^{1}/{}_{2}}}}}=\frac{40}{10}=4\] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}={{\left( \frac{1}{2} \right)}^{4}}\] \[\frac{125}{{{N}_{0}}}=\frac{1}{16}\] \[{{N}_{0}}=2000g\]
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