NEET Sample Paper NEET Sample Test Paper-9

  • question_answer \[100\text{ }ml\] of \[\frac{N}{10}HCl\] are mixed with 300 ml of \[\frac{N}{20}\] \[HN{{O}_{3}}\]. The normality of the resulting solution will be

    A)  \[\frac{N}{15}\]                                           

    B)  \[\frac{N}{20}\]

    C)  \[\frac{N}{16}\]                                              

    D)  \[\frac{N}{18}\]

    Correct Answer: C

    Solution :

    \[100\text{ }ml\] of \[\frac{N}{10}HCl=\frac{1}{100}g.\] \[eq=0.01\,g\,\,eq\] \[300\,\,ml\] of \[\frac{N}{20}HN{{O}_{3}}=\frac{1}{20}\times \frac{1}{1000}\times 300\]                 \[=0.015\,g\,\,eq\] Total acid \[=0.01+0.015\]                 \[=0.025\,\,geq.\]                 \[=\frac{1}{40}\,g\,\,eq.\] Total volume \[=400\,ml\] \[\therefore \]   Normality  \[=\frac{{\scriptstyle{}^{1}/{}_{40}}}{400}\times 1000=\frac{1}{16}\]

adversite


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