A) \[153.12g\] of \[KCl{{O}_{3}}\]
B) \[122.5\text{ }g\] of \[KCl{{O}_{3}}\]
C) \[245\,g\] of \[KCl{{O}_{3}}\]
D) \[98\text{ }g\] of \[KCl{{O}_{3}}\]
Correct Answer: A
Solution :
\[\begin{matrix} 2KCl{{O}_{3}} \\ 2(39+35.5+48) \\ =245\,g \\ \end{matrix}\,\,\,\,\,\,\begin{matrix} \xrightarrow{{}} \\ {} \\ {} \\ \end{matrix}\,\,\,\,\,\,\begin{matrix} 2KCl+3{{O}_{2}} \\ 3\times 32 \\ =96g \\ \end{matrix}\] \[48\,\,g\] \[{{O}_{2}}\] will be produced from \[KCl{{O}_{3}}\] \[=\frac{245}{96}\times 48=122.5\,g\] \[80%\] pure \[KCl{{O}_{3}}\]required \[=\frac{100}{80}\times 122.5\] \[=153.12\,g\]
You need to login to perform this action.
You will be redirected in
3 sec
