A) \[{{H}_{3}}C-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{D}_{3}}\]
B)
C) \[{{H}_{3}}C-\underset{Cl}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{2}}C{{H}_{3}}\]
D)
Correct Answer: D
Solution :
Compound has plane of symmetry so it will not show optical activity.
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