2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-9

  • question_answer
    What will be the angular width of central maxima in fraunhofcr diffraction, when tight of wavelength \[(6000\overset{o}{\mathop{A}}\,)\] is used and slit width is \[12\times {{10}^{-5}}cm\]:

    A)  2rad               

    B)  3 rad

    C)  1 rad             

    D)  2 rad

    Correct Answer: C

    Solution :

    As, angular width \[\theta =\frac{2\lambda }{d}=\frac{2\times 6000\times {{10}^{-1}}}{12\times {{10}^{-5}}\times {{10}^{-2}}}=1\,\,rad\] Note that the diffracted light is distributed in between, \[-\frac{\lambda }{d}\]to \[+\frac{\lambda }{d}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner