• # question_answer A parallel plate capacitor has two layers of dielectrics as shown in figure. The capacitor is connected across a battery, the ratio of potential difference across the dielectric layers is: A)  $4/3$                         B)  $1/2$C)  $1/3$                         D)  $3/2$

Suppose electric field in dielectric are ${{E}_{1}}$ and ${{E}_{2}}$                 $\Rightarrow$               $\frac{\Delta {{V}_{1}}}{\Delta {{V}_{2}}}=\frac{{{E}_{1}}d}{{{E}_{2}}2d}=\frac{3}{2}$    $\left( \because \,\,\frac{{{E}_{1}}}{{{\varepsilon }_{1}}}=\frac{{{K}_{2}}}{{{K}_{1}}}=3 \right)$