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NEET Sample Paper NEET Sample Test Paper-9

  • question_answer
    A dipole has its moment \[p\] is kept at the centre of a ring of radius R and charge q. The dipole moment has its direction along the axis of the ring. The resultant force on the ring due to the dipole is:

    A)  zero                            

    B)  \[\frac{pq}{4\pi {{\varepsilon }_{0}}{{R}^{3}}}\]

    C)  \[\frac{pq}{2\pi {{\varepsilon }_{0}}{{R}^{3}}}\]               

    D)  \[\frac{pq}{4\pi {{\varepsilon }_{0}}{{R}^{3}}},\] only if the charge uniformly distributed on the ring.

    Correct Answer: B

    Solution :

    The electric field due to the dipole on the circumference of the ring, \[E=\frac{P}{4\pi {{\varepsilon }_{0}}{{R}^{3}}}\] and it is directed normal to the plane charged ring. Hence, force on the charged ring             \[F=qE=\frac{Pq}{4\pi {{\varepsilon }_{0}}{{R}^{3}}}\]


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