A) \[r\]
B) \[\frac{r}{2}\]
C) \[\frac{2r}{3}\]
D) \[\frac{3r}{2}\]
Correct Answer: C
Solution :
For points A and C, loop BCD is short circuited Hence\[,\] \[{{R}_{AC}}=\frac{r\times 2r}{3r}=\frac{2}{3}r\].You need to login to perform this action.
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