2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-8

  • question_answer
    A mixture of formic acid and oxalic acid is heated with concentrated \[{{H}_{2}}S{{O}_{4}},\] The gaseous product is passed into \[KOH\] solution where the volume decreases by \[\frac{1}{6}\] th. The molecular proportion of the organic acids, formic acid and oxalic acid in the mixture is

    A)  \[4:1\]            

    B)  \[1:4\]

    C)  \[1:2\]                         

    D)  \[2:1\]

    Correct Answer: A

    Solution :

    Let mole of \[HCOOH=x\] mole of \[{{H}_{2}}{{C}_{2}}{{O}_{4}}=y\] \[\underset{x}{\mathop{HCOOH}}\,+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}\underset{x}{\mathop{CO}}\,+{{H}_{2}}O+{{H}_{2}}S{{O}_{4}}\] \[\underset{y}{\mathop{{{H}_{2}}{{C}_{2}}{{O}_{4}}}}\,+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}\underset{y}{\mathop{CO}}\,+\underset{y}{\mathop{C{{O}_{2}}SOl4}}\,+{{H}_{2}}O+{{H}_{2}}S{{O}_{4}}\] Total gaseous products \[=x+2y\] Only \[C{{O}_{2}}\] is absorbed by \[KOH,\]y mole \[\therefore \]  \[\frac{y}{x+2y}=\frac{1}{6}\]                 \[x+2y=6y\]                 \[x=4y\]                 \[\frac{x}{y}=\frac{4}{1}\]        


You need to login to perform this action.
You will be redirected in 3 sec spinner