2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-8

  • question_answer
    The magnifying power of an astronomical teleshope in normal adjustment is 8 and the distance between the two lenses is 54 cm. The focal length of eye lens and objective lens will be respectively:

    A)  6 cm and 48 crn    

    B)  48 cm and 6 cm

    C)  8 cm and 64 cm    

    D)  64 cm and 8 cm

    Correct Answer: A

    Solution :

    As,  \[m=\frac{{{F}_{0}}}{{{F}_{e}}}\] and \[{{F}_{0}}+{{F}_{e}}=54cm\] \[{{F}_{e}}=6cm\]  and \[{{F}_{0}}=48cm\] (as \[m=8\])


You need to login to perform this action.
You will be redirected in 3 sec spinner