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NEET Sample Paper NEET Sample Test Paper-8

  • question_answer
    The radius of hydrogen atom in its ground state is \[5.3\times {{10}^{-11}}m.\]. After collision with an electron is found to have a radius of \[21.2\times {{10}^{-11}}m\]. What is the principal quantum number n of the final state of atom?

    A)  \[n=4\]               

    B)  \[n=2\]

    C)  \[n=16\]                    

    D)  \[n=3\]

    Correct Answer: B

    Solution :

    The radii of H-atom and the electron can be related as       \[{{n}^{2}}\times 5.3\times {{10}^{-11}}=21.2\times {{10}^{-11}}\] \[\Rightarrow \]               \[{{n}^{2}}=4\]                 \[n=2\]


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