A) \[40\text{ }ml\]
B) \[20\text{ }ml\]
C) \[10\text{ }ml\]
D) \[\text{4 }ml\]
Correct Answer: A
Solution :
Normality of oxalic acid solution \[=\frac{6.3}{250}\times \frac{1000}{63}=0.4N\] \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[10\times 0.4={{V}_{2}}\times 0.1\] \[{{V}_{2}}=40\,\,ml\]
You need to login to perform this action.
You will be redirected in
3 sec
