A) \[1:1\]
B) \[1:3\]
C) \[1:9\]
D) None of these
Correct Answer: C
Solution :
Energy of an electron in ground state of an atom (Bohr's hydrogen atom like) is given as \[\varepsilon =-13.6{{Z}^{2}}eV,\] where, Z = atomic number of the atom \[\Rightarrow \] The ionization energy of that atom \[={{\varepsilon }_{iron}}=-(-13.6){{Z}^{2}}=13.6{{Z}^{2}}\] \[={{({{\varepsilon }_{iron}})}_{H}}|{{({{\varepsilon }_{iron}})}_{Li}}=\frac{{{({{Z}_{H}})}^{2}}}{{{({{Z}_{Li}})}^{2}}}\] \[\Rightarrow \] \[\frac{{{\left( {{\varepsilon }_{ion}} \right)}_{H}}}{{{\left( {{\varepsilon }_{ion}} \right)}_{Li}}}={{\left( \frac{1}{3} \right)}^{2}}=\frac{1}{9}.\]
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