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NEET Sample Paper NEET Sample Test Paper-6

  • question_answer
    On a humid day in summer, the mole fraction of gaseous \[{{H}_{2}}O\] (water vapour) in the air at \[{{25}^{o}}C\] can be as high as\[0.0287\]. Assuming a total pressure of \[0.977\] atm. What is the partial pressure of dry air?

    A)  \[94.9\]atm                 

    B)  \[0.949\]atm

    C)  \[949\]atm                  

    D)  \[0.648\]atm

    Correct Answer: B

    Solution :

    \[{{P}_{{{H}_{2}}O}}={{X}_{{{H}_{2}}O}}{{P}_{Total}}\] \[=0.0287\times 0.977=0.028\,\,atm\] \[{{P}_{Total}}={{P}_{dryair}}+{{P}_{{{H}_{2}}O}}\] \[{{P}_{dryair}}={{P}_{Total}}-{{P}_{{{H}_{2}}O}}\] \[0.977-0.028=0.949\,atm\]


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