A) \[{{g}_{p}}-\frac{1}{4}R{{\omega }^{2}}\]
B) \[{{g}_{p}}-\frac{3}{4}\,\,{{\omega }^{2}}\]
C) \[{{g}_{p}}-R\,{{\omega }^{2}}\]
D) \[{{g}_{p}}+\frac{1}{2}R\,{{\omega }^{2}}\]
Correct Answer: A
Solution :
As we know that the gravitational acceleration At \[g'={{g}_{p}}-R{{\omega }^{2}}\,{{\cos }^{2}}\lambda \] \[\lambda ={{60}^{o}}\] \[g'={{g}_{p}}-\frac{R{{\omega }^{2}}}{4}\]
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