A) \[\frac{2.303}{5.48\times {{10}^{-14}}}\log 3\]
B) \[\frac{2.303}{5.48\times {{10}^{-14}}}\log 2\]
C) \[\frac{2.303}{5.48\times {{10}^{-14}}}\log \frac{1}{3}\]
D) \[\frac{2.303}{5.48\times {{10}^{-14}}}\log \frac{2}{3}\]
Correct Answer: A
Solution :
For two third of a reaction, \[[{{A}_{0}}]=\alpha \] \[[A]=a-\frac{2}{3}a=\frac{a}{3}\] \[{{t}_{2/3}}=\frac{2.303}{k}\log \frac{{{[A]}_{0}}}{[A]}\] \[=\frac{2.303}{5.48\times {{10}^{-14}}}\log \frac{a}{{\scriptstyle{}^{a}/{}_{3}}}=\frac{2.303}{5.48\times {{10}^{-14}}}\log 3\]
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