NEET Sample Paper NEET Sample Test Paper-5

  • question_answer
    In Young's double slit experiment the width of one slit is double that of the other, the ratio of intensity of a bright band to that of a dark band in the interference pattern will be:

    A)  \[2:1\]                        

    B)  \[3:1\]

    C)  \[6:1\]                         

    D)  \[9:1\]

    Correct Answer: D

    Solution :

    We have \[\frac{{{l}_{\max }}}{{{\operatorname{l}}_{\min }}}={{\left( \frac{\sqrt{{{l}_{1}}}+\sqrt{{{l}_{2}}}}{\sqrt{{{l}_{1}}}-\sqrt{{{l}_{2}}}} \right)}^{2}}=\frac{9}{1}\]   \[(\because \,{{l}_{1}}=4/2)\]


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