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NEET Sample Paper NEET Sample Test Paper-5

  • question_answer
    If the de-Broglie wavelength of proton is \[1.0\times {{10}^{-13}}m,\]the electric potential through which it must have been accelerated is:

    A)  \[4.07\times {{10}^{4}}V\]            

    B)  \[8.2\times {{10}^{4}}V\]

    C)  \[8.2\times {{10}^{3}}V\]              

    D)  \[4.07\times {{10}^{5}}V\]

    Correct Answer: B

    Solution :

    As           \[V=\frac{{{h}^{2}}}{2me{{\lambda }^{2}}}\] After putting the data of the values from the question, in equation, we get.             \[V=8.2\times {{10}^{4}}V\]


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