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NEET Sample Paper NEET Sample Test Paper-5

  • question_answer
    An equilateral triangular loop having a resistance R and length of each side I is placed in a magnetic field which is varying at \[\frac{d\,\,B}{dt}=\frac{l\,T}{S}\]. The induced current in the loop will be:            

    A)  \[\frac{\sqrt{3}}{4}\,\frac{{{l}^{2}}}{R}\]                             

    B)  \[\frac{4}{\sqrt{3}}\,\frac{{{l}^{2}}}{R}\]

    C)                  \[\frac{\sqrt{3}}{4}\,\frac{R}{{{l}^{2}}}\]                              

    D)  \[\frac{4}{\sqrt{3}}\,\frac{R}{{{l}^{2}}}\]

    Correct Answer: A

    Solution :

    As            \[\phi =\frac{\sqrt{3}}{4}{{l}^{2}}B\] Therefore, induced emf             \[\varepsilon =\left| \frac{d\phi }{dt} \right|=\frac{\sqrt{3}}{4}{{l}^{2}}\frac{dB}{dt}\]                 \[i\Rightarrow \frac{\varepsilon }{R}=\frac{\sqrt{3}{{l}^{2}}}{4R}\] (Here i = induced current).


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