A) \[U(x)=\frac{K\,{{(x-a)}^{2}}}{2}\]
B) \[U(x)={{K}_{1}}x+{{K}_{2}}{{x}^{2}}+{{K}_{3}}{{x}^{3}}\]
C) \[U(x)=A{{e}^{-bx}}\]
D) U(x) = constant
Correct Answer: A
Solution :
\[U(x)=\frac{K{{(x-a)}^{2}}}{2}\]
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