A) 162.2 ml
B) 262.2 ml
C) 362.2 ml
D) 462.2 ml
Correct Answer: B
Solution :
Given at \[{{T}_{1}}\,\,=\,\,300\,\,K,\,\,{{T}_{2}}\,\,=\,\,273\,K\,(STP)\] \[{{V}_{1}}=300\,\,ml\,\,=\,\,\left( \frac{300}{1000} \right)\,litre,\] \[{{P}_{1}}\,\,=\,\,\left( \frac{730}{760} \right)\,atm.\,\,\,{{P}_{2}}\,=\,1\,atm.,\,\,{{V}_{2}}\,\,=\,\,?\,\] \[\because \,\,\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}\,\,=\,\,\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}},\,\,\frac{730\times 300}{760\times 1000\times 300}\,\,=\,\,\frac{l\times {{V}_{2}}}{273}\] \[\therefore \,\,V=0.2622\,\,litre\,\,=\,\,262.2\,\,ml.\]
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