A) \[12\text{ }m/se{{c}^{2}}\]
B) \[4\text{ }m/se{{c}^{2}}\]
C) \[10\text{ }m/se{{c}^{2}}\]
D) zero
Correct Answer: B
Solution :
As the mass of 10 kg. has acceleration \[12\text{ }m/se{{c}^{2}}\] therefore it apply 120 N force on mass 20 kg. in backward direction. \[\therefore \] Net forward force on \[20\text{ }kg.\,mass=200-120\] \[=\,\,80\,N\] \[\therefore \,\,\,Acceleration=\,\,\frac{80}{20}=4\,m/se{{c}^{2}}\]You need to login to perform this action.
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