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NEET Sample Paper NEET Sample Test Paper-54

  • question_answer
    A magnet is suspended in such a way that it oscillates in the horizontal plane. It makes 20 oscillations per minute at a place where dip angle is \[30{}^\circ \] and 15 oscillations per minute at a place where dip angle is \[60{}^\circ \]. The ratio of the total earth?s magnetic field at the two places is-

    A) \[3\sqrt{3}\,\,:\,\,8\]                   

    B) \[16\,\,:\,\,9\sqrt{3}\]

    C) \[4\,\,:\,\,9\]                   

    D) \[2\sqrt{3}\,\,:\,\,9\]

    Correct Answer: B

    Solution :

    \[T\,\,\propto \,\,\frac{1}{\sqrt{B}}\] \[\frac{3}{4}\,\,=\,\,\frac{{{B}_{{{H}_{2}}}}}{{{B}_{{{H}_{1}}}}}\,\,=\,\,\frac{B{{e}_{2}}\,\cos \,\,60{}^\circ }{B{{e}_{1}}\,\cos \,\,30{}^\circ }\,\,\] \[\Rightarrow \,\,\,\,\,\frac{B{{e}_{1}}}{B{{e}_{2}}}\,=\,\,\frac{16}{9\sqrt{3}}\]


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