2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-54

  • question_answer
    If the bond dissociation energies of XY, Xz and Yz (all diatomic molecules) are in the ratio \[1\text{ }:\text{ }1\text{ }:\text{ }0.5\] and \[{{\Delta }_{f}}H\] of XY is\[-200\text{ }kJ\text{ }mo{{l}^{-1}}\]. The mol dissociation energy of Xs will be-

    A) \[800\text{ }kJ\text{ }mo{{l}^{-1}}\]    

    B) \[200\text{ }kJ\text{ }mo{{l}^{-1}}\]

    C) \[300\,\,kJ\,\,mo{{l}^{-1}}\]     

    D) \[400\,\,kJ\,\,mo{{l}^{-1}}\]

    Correct Answer: A

    Solution :

    \[{{X}_{2}}+{{Y}_{2}}\,\,\to \,\,XY\,\,\,\,\,\,~\Delta H=-\,200\text{ }kJ/mol\] \[\Delta H=\sum B.\,{{E}_{in}}\,\,-\,\,\sum B\,\,.\,\,{{E}_{out}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner