A) \[{{y}_{B}}=2{{y}_{A}}\]
B) \[{{y}_{A}}={{y}_{B}}\]
C) \[{{y}_{B}}=3{{y}_{A}}\]
D) \[{{y}_{A}}=3{{y}_{B}}\]
Correct Answer: D
Solution :
\[As,\,\,\frac{{{Y}_{A}}}{{{Y}_{B}}}=\frac{\tan \,{{\theta }_{A}}}{\tan \,{{\theta }_{B}}}=\,\frac{\tan \,60{}^\circ }{\tan \,30{}^\circ }\,\,=\,\,\frac{\sqrt{3}}{1/\sqrt{3}}\,\,=\,\,3\] \[\Rightarrow \,\,\,{{Y}_{A}}=3{{Y}_{B}}\]
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