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NEET Sample Paper NEET Sample Test Paper-54

  • question_answer
    Half a mole of helium at \[27{}^\circ C\] and at a pressure of 2 atmosphere is mixed with 1.5 mole of \[{{N}_{2}}\] at \[77{}^\circ C\] and at a pressure at 5 atmosphere so that the volume of the mixture is equal to the sum of their initial volumes. If the temperature of the mixture is \[69{}^\circ C\], its pressure in atmosphere is-

    A) 3.5                               

    B) 3.8

    C) 3.95                             

    D) 4.25

    Correct Answer: B

    Solution :

    \[V={{V}_{1}}+{{V}_{2}}\] \[\frac{nRT}{P}=\frac{{{n}_{1}}R{{T}_{1}}}{{{P}_{1}}}+\frac{{{n}_{2}}R{{T}_{2}}}{{{P}_{2}}}\] \[\frac{2R342}{P}\,\,=\,\,\frac{0.5R300}{2}\,\,+\,\,\frac{1.5R\times 350}{5}\] \[\frac{684}{P}\,\,=\,\,75+105\] \[P\,\,=\,\frac{684}{180}\,\,=\,3.8\]


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