question_answer

Plotting a graph of \[\log \,\,{{t}_{1/2}}\] against log \[\log \,\,{{[A]}_{0}}\] of a reactant for a first order reaction, the slope will be-

A) -1        

B)               -2

C) 0                                 

D) +1

Correct Answer: C

Solution :

\[{{t}_{1/2}}\,=\,\,\frac{0.693}{k}\] \[log\text{ }{{t}_{1/2}}=log\text{ }0.693\,\,-\,\,log\text{ }k=constant\]