2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-53

  • question_answer
    A crystal is made of particles A and B. A forms FCC packing and B occupies all the octahedral voids. If all the particles along the plane as shown in figure are removed, then, the formula of the crystal would be:

    A) \[AB\]   

    B) \[{{A}_{5}}{{B}_{7}}\]

    C) \[{{A}_{7}}{{B}_{5~}}\]                    

    D) \[{{A}_{2}}{{B}_{3}}\]

    Correct Answer: A

    Solution :

    \[{{A}_{\frac{4}{8}+\frac{4}{2}}}\] \[{{B}_{4-1-\frac{2}{4}}}\] \[{{A}_{2.5}}\,{{B}_{2.5}}\,or\,\,AB\]              


You need to login to perform this action.
You will be redirected in 3 sec spinner