A) The output voltage is 1000 V
B) The output power is 9 Kw
C) The current in the primary is 50 A
D) The current in the second is 10 A
Correct Answer: D
Solution :
\[{{E}_{s}}\,\,=\,\,\frac{{{N}_{S}}}{{{N}_{P}}}\,\times \,{{E}_{P}}\,\,=\,\,1000\,V\] Output power \[=\,\,10\,kw\times \frac{90}{100}\] \[\And \,\,{{I}_{P}}\,=\,\,\frac{{{P}_{\operatorname{input}}}}{{{E}_{P}}}\,=\,\,\frac{10,000}{200}\] Hence\[{{I}_{P}}=\,\,50A\]]
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