A) 3 times
B) 9 times
C) \[\frac{1}{2}\,\,times\]
D) \[\frac{1}{9}\,\,times\].
Correct Answer: C
Solution :
\[\,\lambda =\frac{h}{\sqrt{2mE}}\] \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\,\,=\,\,\sqrt{\frac{{{E}_{2}}}{{{E}_{1}}}}\,\,=\,\,\sqrt{\frac{9{{E}_{1}}}{{{E}_{1}}}}\,\,=\,\,3\] \[{{\lambda }_{2}}\,\,=\,\,\frac{1}{3}\,{{\lambda }_{1}}\]
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