A) \[\frac{105}{107}\,E\]
B) \[\frac{107}{105}\,E\]
C) \[\frac{52}{51}\,E\]
D) \[\frac{51}{52}\,E\]
Correct Answer: B
Solution :
\[{{K}_{\alpha }}=Q\times \frac{{{m}_{y}}}{{{m}_{y}}+{{m}_{\alpha }}}\] \[E=Q.\,\,\frac{210}{214}\,\,\Rightarrow \,\,Q=\frac{214E}{210}\]
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