NEET Sample Paper NEET Sample Test Paper-53

  • question_answer
    If the length of the double helical DNA is 1.7 meters. The numbers of base pairs present in the DNA is

    A) \[5\times {{10}^{9}}\]             

    B) \[1.7\times {{10}^{9}}\]

    C) \[3.4\times {{10}^{9}}\]                      

    D) \[1.7\times {{10}^{5}}\]

    Correct Answer: B

    Solution :

    \[1\text{ }m\text{ }=\text{ }{{10}^{10}}\,\overset{{}^\circ }{\mathop{A}}\,\] and pitch of one turn of double helix of DNA is \[34\,\,\overset{{}^\circ }{\mathop{A}}\,\] in which 10 base pairs are present.


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