question_answer

The compound \[{{\left( Si{{H}_{3}} \right)}_{3}}N\] is expected to be:

A) pyramidal and more basic than \[{{(C{{H}_{3}})}_{3}}N\]

B) planar and less basic than \[{{(C{{H}_{3}})}_{3}}N\]

C) pyramidal and less basic than \[{{(C{{H}_{3}})}_{3}}N\]

D) planer and more basic than \[{{(C{{H}_{3}})}_{3}}N\]

Correct Answer: B

Solution :

Due to \[P\pi -d\pi \] back bond