2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-52

  • question_answer
    The decomposition of certain mass of \[CaC{{O}_{3}}\] gave \[11.2\text{ }d{{m}^{3}}\] of \[C{{O}_{2}}\] gas at STP. The mass of KOH required to completely neutralize the gas is

    A) 56 g                             

    B) 28 g

    C) 42 g                             

    D) 20 g

    Correct Answer: A

    Solution :

    \[2\text{ }KOH+C{{O}_{2}}\to {{K}_{2}}C{{O}_{3}}+{{H}_{2}}O\] 1 mol                1 mol \[2\,\,\times \,\,56\text{ }gm~~\]             \[22.4\,\,litre\] 11.2 litre \[C{{O}_{2}}\] will neutralize by 56 gm of KOH


You need to login to perform this action.
You will be redirected in 3 sec spinner