A) \[{{\sin }^{-1}}\,(n)\]
B) \[{{\sin }^{-1}}\,(1/n)\]
C) \[{{\tan }^{-1}}\,(1/n)\]
D) \[{{\tan }^{-1}}\,(n)\]
Correct Answer: D
Solution :
Brewster?s law tan \[{{i}_{p}}=n\]
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