• # question_answer For the reaction $Sn{{O}_{2}}_{(s)}+2{{H}_{2}}_{(g)}\rightleftharpoons \,\,2{{H}_{2}}{{O}_{(g)}}+S{{n}_{\text{(}\ell \text{)}}}$ at 900 K, the equilibrium steam hydrogen mixture was found to be $40%\text{ }{{H}_{2}}$ by volume the ${{K}_{p}}$ is: A) 1.15                 B) 2.25C) 7.75                             D) 10

${{K}_{p}}={{K}_{c}}\,=\,\,\frac{{{[{{H}_{2}}O]}^{2}}}{{{[{{H}_{2}}]}^{2}}}\,\,=\,\,\frac{60\times 60}{40\times 40}$