• # question_answer To dissolve 3.3g of certain metal 110mL of $1N{{H}_{2}}S{{O}_{4}}$. Find the equivalent mass of metal- A) 15 g                             B) 30 gC) 20 g                             D) 10 g

$meq.\text{ }of\text{ }{{H}_{2}}S{{O}_{4}}=110\times 1=110$ $Equivalent\text{ }of\text{ }{{H}_{2}}S{{O}_{4}}=110\times {{10}^{-}}^{3}$ now according to law, equivalents of ${{H}_{2}}S{{O}_{4}}=\text{ }equivalents\text{ }of\text{ }metal$ $\therefore \,\,\text{ }equivalent\text{ }of\text{ }metal\,\,=\,\,110\,\,\times \,\,{{10}^{-3}}$ $now\text{ }equivalent\,\,=\,\,\frac{weight}{GEM}$ $110\,\,\times \,\,{{10}^{-}}^{3}=\text{ }\frac{3.3}{GEM}\,\text{ }GEM\,\,=\,\,30$