A) 15 g
B) 30 g
C) 20 g
D) 10 g
Correct Answer: B
Solution :
\[meq.\text{ }of\text{ }{{H}_{2}}S{{O}_{4}}=110\times 1=110\] \[Equivalent\text{ }of\text{ }{{H}_{2}}S{{O}_{4}}=110\times {{10}^{-}}^{3}\] now according to law, equivalents of \[{{H}_{2}}S{{O}_{4}}=\text{ }equivalents\text{ }of\text{ }metal\] \[\therefore \,\,\text{ }equivalent\text{ }of\text{ }metal\,\,=\,\,110\,\,\times \,\,{{10}^{-3}}\] \[now\text{ }equivalent\,\,=\,\,\frac{weight}{GEM}\] \[110\,\,\times \,\,{{10}^{-}}^{3}=\text{ }\frac{3.3}{GEM}\,\text{ }GEM\,\,=\,\,30\]
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