A) \[C{{O}_{2}},\text{ }N{{H}_{3}},\text{ }{{O}_{2}}\]
B) \[N{{H}_{3}},\text{ }{{O}_{2}},\text{ }C{{O}_{2}}\]
C) \[{{O}_{2}},\text{ }N{{H}_{3}},\text{ }C{{O}_{2}}\]
D) \[N{{H}_{3}},\text{ }C{{O}_{2}},\text{ }{{O}_{2}}\]
Correct Answer: D
Solution :
\[Number\text{ }of\text{ }atoms\text{ }of\,\,C{{O}_{2}}=3\times \left( \frac{10}{44} \right)\times N\] \[Number\text{ }of\text{ }atoms\text{ }of\,\,N{{H}_{3}}=4\times \left( \frac{10}{17} \right)\times N\]\[Number\text{ }of\text{ }atoms\text{ }of\,\,{{O}_{2}}=2\times \left( \frac{10}{32} \right)\times N\] Here N is Avogadro?s number. Hence the correct order is: \[N{{H}_{3}},\,\,C{{O}_{2}},\,\,{{O}_{2}}\]
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