NEET Sample Paper NEET Sample Test Paper-51

  • question_answer The equation of projectile is \[y=16x-\frac{5{{x}^{2}}}{4}\] The horizontal range is-

    A) 16 m                

    B) 8 m

    C) 3.2 m               

    D) 12.8 m

    Correct Answer: D

    Solution :

    \[\because \,\,\,y=x\,\tan \,\theta \left( 1-\frac{x}{R} \right)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,.....(1)\] \[and\,\,y\,\,=\,\,16x-\frac{5{{x}^{2}}}{4}\] \[\Rightarrow \,\,\,\,\,y\,\,=\,\,16x\,\,\left( 1-\frac{5x}{64} \right)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,.....(2)\] \[comparing\text{ }\left( 1 \right)\,\,\And \,\,\left( 2 \right),\text{ }R=\frac{64}{5}=12.8\text{ }m\]

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