• # question_answer $\left( v-x \right)$ curve is shown for a particle moving in a straight line. The acceleration of the particle will- A) increases with x parabolicallyB) remain constantC) increase linearly with xD) none of the above

From graph $v=mx-c$ $\frac{dv}{dt}=m\frac{dx}{dt}$ $={{m}^{2}}x-mc$