NEET Sample Paper NEET Sample Test Paper-51

  • question_answer The frequency of a vibrating wire is\[f\]. If  tension is doubled, density is halved and diameter is doubled, then the new frequency will be-

    A) \[f\]                              

    B)  \[f\sqrt{2}\]

    C) \[2f\]                            

    D) \[4f\]

    Correct Answer: A

    Solution :

    If l be the length of the wire then frequency \[f=\frac{1}{lD}\,\sqrt{\frac{T}{\pi \rho }}\] When tension T is doubled, density p is halved, diameter D is doubled f would remain the same.


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