NEET Sample Paper NEET Sample Test Paper-51

  • question_answer A simple pendulum with a solid metal bob has a period T. The metal bob is now immersed in a liquid having density one-tenth that of the metal of the bob. The liquid is non-viscous. Now the period of the same pendulum with its bob remaining all the time in the liquid will be

    A) \[\frac{9}{10}\,T\]                     

    B) \[T\sqrt{\frac{10}{9}}\]

    C) unchanged                    

    D) \[T\sqrt{\frac{9}{10}}\]

    Correct Answer: B

    Solution :

    \[T=2\pi \sqrt{\frac{\ell }{g}}\] In a liquid \[T'=2\pi \sqrt{\frac{\ell }{g\left\{ 1-\frac{1}{\sigma } \right\}}}\] \[\sigma =\frac{density\,\,of\,\,bob}{density\,\,of\,\,liquid}\] \[\sigma =10\] \[T'=2\pi \sqrt{\frac{\ell }{g\left\{ 1-\frac{1}{\sigma } \right\}}}\,\,=\,\,2\pi \sqrt{\frac{\ell }{g}}\,\sqrt{\frac{10}{9}}\] \[T'=T\sqrt{\frac{10}{9}}\]

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