question_answer

A thin disc of mass 9M and radius R from which a disc of radius \[R/3\] is cut, as shown in figure. Then moment of inertia of the remaining disc about 0, perpendicular to the plane of disc is-

A) \[4\text{ }M{{R}^{2}}\]                      

B) \[9\text{ }M{{R}^{2}}\]

C) \[\frac{37}{9}\,M{{R}^{2}}\]              

D) \[\frac{40}{9}M{{R}^{2}}\]