A) \[3\,\,\times \,\,{{10}^{8}}m/s~\]
B) \[1.5\times {{10}^{8}}m/s\]
C) \[6\,\,\times \,\,{{10}^{8}}m/s\]
D) \[\sqrt{3}\times {{10}^{8}}m/s\]
Correct Answer: B
Solution :
\[Sin\,\,{{i}_{c}}\,=\,\frac{1}{_{r}{{\mu }_{d}}}\,\,=\,\,\frac{{{\mu }_{r}}}{{{\mu }_{d}}}\,\,=\,\,\frac{{{v}_{d}}}{{{v}_{r}}}\] \[sin\text{ }30{}^\circ \text{ }=\text{ }\frac{{{V}_{d}}}{^{.}3\times {{10}^{8}}}\,\,\Rightarrow \text{ }{{v}_{d}}=1.5\text{ }\times \text{ }{{10}^{8}}m/s\]
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