A) \[A{{l}_{2}}{{O}_{3}}\] goes into solution as soluble \[Al{{\left( OH \right)}_{4}}\] while other basic oxides as \[Ti{{O}_{2}}\] and \[F{{e}_{2}}{{O}_{3}}\] remain insoluble
B) \[A{{l}_{2}}{{O}_{3}}\] changes to AlN which in turn decomposed by \[{{H}_{2}}O\].
C) \[A{{l}_{2}}{{O}_{3}}\] changes to \[A{{l}_{2}}{{\left( C{{O}_{3}} \right)}_{3}}\] which changes to \[AlC{{l}_{3}}\]
D) Cryolite is added to lower the melting point of bauxite
Correct Answer: A
Solution :
\[A{{l}_{2}}{{O}_{3}}+NaOH\to \,\,Na\left[ Al{{\left( OH \right)}_{4}} \right]\]
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