A) \[C{{H}_{2}}=CH-CBr=CHD\]
B) \[C{{H}_{2}}\left( Br \right)-CHDC\equiv CH\]
C) \[DC{{H}_{2}}-CHBrC\equiv CH\]
D) \[C{{H}_{2}}=CH-CD=CHBr\]
Correct Answer: A
Solution :
Resonance stable product is preferred.
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