• # question_answer 44) From the zener diode circuit shown in figure, the current through the zener is- A) 34 mA              B) 31.5 mAC) 36.5 mA                       D) 2.5 mA

${{i}_{1}}\,=\,\frac{50}{20\times {{10}^{3}}}\,\,\,\Rightarrow \,\,2.5\,mA$ $i\,\,=\,\,\frac{220-50}{5\times {{10}^{3}}}\,\,\,\Rightarrow \,\,\frac{170}{5\times {{10}^{3}}}\,\,\Rightarrow \,\,32\,mA$ ${{i}_{1}}+{{i}_{2}}=i$ $2.5+{{i}_{2}}=32$ ${{i}_{2}}\,\,=\,\,31.5\,mA$