• # question_answer ) One mole of ideal gas undergoes cyclic process shown in figure. Process 1 $\to$ 2 is adiabatic. Heat given to gas in the process is (nearly)- A) -59 J                B) -47JC) -42 J                            D) None of these

${{W}_{12}}\,=\,\,-\frac{nR({{T}_{1}}-{{T}_{2}})}{\gamma -1}\,\,=\,\,-\frac{R{{T}_{1}}({{10}^{\frac{\gamma -1}{\gamma }}}-1)}{\gamma -1}$ $=\text{ }-\text{ }5600\text{ }kJ$ ${{W}_{23}}=0$ ${{W}_{31}}\,\,=\,\,nR{{T}_{1}}\text{ }\ell n\left( \frac{V}{V/10} \right)\,\,=\,\,R{{T}_{1}}\text{ }In\text{ }10$ $=\text{ }5552.67\text{ }J$ $\therefore \,\,\,\,\Delta Q\,\,=\,\,{{W}_{net}}=-\,47.33\text{ }J$